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December 26, 2004

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(1)

   

 

  »º º

December 26, 2004

    

(2)

1

 

1

1.1

 

. . . . 1

1.2

 

. . . . 1

1.3



. . . . 2

(3)

1

Ì  

  

  

      

    

 DZ

1.1

  

1.1 (

Ì

)



(1)



n



m



n ≥ m + 1

  

2



(2)



n



m



n ≥ rm + 1

  

r + 1



  

n



m

 

n ≥ rm + 1

 

(r + 1)





1.2

  Ì



x

 

x

 

1

  

{x}

  

x = 2.345 → x = 2 + 0.345 → {x} = 0.345, y = −1.62 → y = −2 + 0.38 → {y} = 0.38, z =

2 → z = 1 + (

2 − 1) → {z} = 2 − 1.

1.2



N

 

α

  

m, n



0 < m + nα < 1

N .



α

 



n

  



(0, 1)



N



 0, 1

N

 ,

 1 N , 2

N

 , · · · ,

 N − 1 N , 1

 .

  

N + 1



{1 · α}, {2 · α}, · · · , {N · α}, {(N + 1) · α} ∈ (0, 1)



2



1 ≤ n ≤ N + 1

(4)

{n 1 α}, {n 2 α}



⎧ ⎪

⎪ ⎩

n 1 α = m 1 + {n 1 α}

n 2 α = m 2 + {n 2 α}

|{n 1 α} − {n 2 α}| < N 1

⇒ |(m 1 − m 2 ) − (n 1 − n 2 )α| < 1 N .

  

m = m 1 − m 2 , n = −n 1 + n 2



m = −(m 1 − m 2 ), n = n 1 − n 2



0 < m + nα < 1

N .

 1.3

½ûDZ

 DZ

5



n



m



mn

 

6



7



n = 23



m = 29



29 × 23 = 667



1990

  DZÆ 

1 2

  

  

1.3



n



m



mn

 

1



0



n = 7



m = 143



143 × 7 = 1001





n + 1

 

n + 1



1, 11, 111, · · · ,

 n

111 · · · 1,

 n+1

111 · · · 1



n

   

n + 1

 

  

n

   

a =

 i

111 · · · 1, b =

 j

111 · · · 1; i < j



n | (b − a) =

 j−i

111 · · · 1

 i

000 · · · 0







1.1



3 × 4

  ! 

 

5



1 G. Berzsenyi, The Roseberry conjecture, Quantum (May 1990).

2 G. Berzsenyi, At siexes and sevens, Quantum (November 1990).

(5)



1.2

  " " 

    " 



3



1.3

 

1

      

  

12 π





1.4

  #$     

 

7

  %   &



1.5



N, p

 

q

 

α

  

m, n



m + nα − q p

< 1 N .



1.6



m

 %

17 · m

 

1



0



m

 





1.7



m

 %

29 · m

 

1



0



m

 



' 

7 × 7



49

  ( # 

)  ( 

 (*   (  (

  (  ( ((

   (

4 × 4



( (

(



3

 º



(6)

+

2n

 



4

 # DZ

 #      #

   #! 

n

 

*

n

   

d n



n = 2

   

2

 

 

d 2 =

2



n = 4

 



d 4 = 1

 Æ 

d n



d 2 =

2, d 3 =

6 − 2, d 4 = 1, d 5 = 2 2 , d 6 = 6 13 , d 7 = 4 − 2

3, d 8 = 6− 2 2 , d 9 = 1 2 , d 14 = 6− 3 2 , d 16 = 1 3 , d 25 = 1 4 .



d 10

 " 

0.421



n

 

d n





2

4

3 · n

 

d 3 = 6 −

2



4

       

    

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