90 ç ×çRŠpç bç
…¿ðÑl„pæ, ~øƬ˙ŸÊ, .™pæU
1. q N = 2131+ 192 (20%)
(i) úkL<£cb n, „p:23n− 1 u 7 íIb
(ii) „p N u 224 íIb
(iii) N uÖýPíb
(iv) N \ 224 Î(F)í¼uÖýPb? w2 log102 = 0.3010.
2. q m ÑøÝŠ5cb (16%)
(i) t„: úL<AÍb n, Xn
k=1
k(k + 1)(k + 2) · · · (k + m) = 1
m + 2· n(n + 1)(n + 2) · · · (n + m + 1)
(ii) ‚à (i) 5!‹, t„:Pn
k=1
k3=n2(n+1)4 2
3. Õøt£ä 4 Ÿ, |ÛõbYåÑ a1, a2, a3, a4 t° (16%) (i) max{a1, a2, a3, a4} = 4 5œ0
(ii) a1≤ a2≤ a3≤ a4 5œ0
4. qšÑ r íÆqQ£ÆÕ~£ n i$íÞ }Ñ sn, tn (16%)
(i) ° s8: t8
(ii) J sn: tn= 3 : 4, °n
5. Þ,úõ O, A, B, 7/ OA = OB = 1, ∠AOB = θ, (0 < θ < π) qõ P ÊJ B Ñÿõ, ¬õ O Dõ A íò( ` ÑÄ(íÓ(,‰, 1pOA= ~a,−→ OB= ~b,−→ OP = ~p−→ (16%)
(i) t„:(~p · ~a)2− 2(~p · ~b) + 1 = 0
(ii) ç(¨ OP z ∠AOB ù}v, / OP = 2, ° θ M
6. *õ P (−1, 1,√
5) }²Þ E : 3x + 4y − 6 = 0 £Þ F : x − 2y + 2√
5z + 3 = 0 T(, w
—}Ñ A, B sõ (16%)
(i) °õ A, B íè™
(ii) ° ∆P AB íÞ
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