100-1電機與電子群 專業科目(一) 共 2 頁 第 1 頁
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學年四技二專第一次聯合模擬考試
電機與電子群 專業科目(一) 詳解
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100-1-04-4
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第一部份:基本電學
1. (A) 1ev=1.6×10−19J (B) 1kWh=3.6×106J (D) 某電動機在輸出功率維持不變的情形下,當損失 功率愈大,則其效率愈小 2. ∵ 3 1 2 R3 R1 R2 I V I V I V > > ⇒ > > 3. T 100C 20 T 80 T 40 60 o o o ⇒ = ° + + = 4. R 4 E R ) R 2 E ( P 2 2 = × = 串 R E R ) R E ( P 2 2 = × = 並 ∴ 4 1 R E R 4 E P P 2 2 = = 並 串 5. 4A ) 18 // 3 ( 9 ) 18 // 3 ( 18 I = + × = 6. (D) 20 Ω/80 W、10 Ω/30 W 如右圖,取I=I2 Ω = + =20 10 30 R串 W 90 30 ) 3 ( P串= 2× = 7. 3 2 2 2 1 2 3 2 1 R E R E R E P P P: : = : : (∵並聯) 3 4 6 4 1 3 1 2 1 : : : : = = 8. P=I2×R⇒P∝R(∵串聯) Ω = ⇒ = R 30 45 R W 75 W 50 1 1 9. V1=2×(6+3)=18V, 3A 6 18 6 V I1= 1= = A 5 2 I I2= 1+ = ,V2=2.4I2+V1=12+18=30V A 10 3 V I3= 2 = ,I=I3+I2=15A V 45 30 15 V I 1 E= × + 2= + = 10. Rth= 10Ω V 75 10 5 V 25 Eth = + × = W 90 5 . 2 ) 5 . 2 10 75 ( P2.5 2× = + = 11. A 4 3 5 . 7 // ) 25 5 ( 15 3 18 I S 1 = + + + = 打開: A 2 3 ) 5 . 7 15 //( ) 5 10 ( 3 18 I S 2 = + + + = 關閉: ∴ 2 4 3 2 3 I I 1 2 = = 12. = − + − = 0 I 3 I 5 2 5 A 6 I A B A 15 5 2 6 3 I 5 B= × + − = ⇒ A 3 IB= 13. 0 V 0V 4 4 V 3 V 6 6 V A A A A− + + + = ⇒ = V 3 4 4 V 3 VAB = × A+ = 14. RN=3//6=2Ω, ) 3A 6 36 ( 3 9 6 I IN= ab= + + − = 15. 6V 6 3 3 ) 36 ( 6 3 6 9 2 6 V Vth ab = + × − + + × + × = = 16. 2 2 ' V 2 4 ' V 6 − = + − ,6−V'+8=2V'−4 V 6 ' V 18 ' V 3 = ⇒ = ⇒ ,∴ 0A 4 ' V 6 I= − = 17. RL =Rth =2+3+3=8Ω 18. Vth =5V,Rth=3//6=2Ω100-1電機與電子群 專業科目(一) 共 2 頁 第 2 頁 W 125 . 3 8 25 2 4 5 P 2 RL = = × = 19. 2A I I I 3A ) 2 1 ( 1 3) (3 I1 = ⇒ 2= 1+ = + × + = ∴ (1 2)//(3 3)] 3 10 30V 2 3 5 . 6 [ I E= 2× + + + + = × = 20. (A) E=0, r Q 4 1 V × πε = (B) 2 r Q 4 1 E × πε = , r Q 4 1 V × πε = (C) R Q 4 1 V × πε = , 2 R Q 4 1 E × πε = 21. QT=150×[(3+2+4)//6//18]µF=450µC C 100 4 2 3 2 C 450 Q2 F = µ + + × µ = µ 22. QT=30V×(9//18)µF=180µC mJ 8 . 1 J 1800 9 2 180 C 2 Q W 2 1 2 T 1 = µ = × = = 23. 2.5 2 5 1000 10 2 400 10 2 5 5 A B = = × × = µ µ − − 24. M=0.5 4×16=4mH(互消) mH 7 12 28 48 4 2 16 4 4 16 4 L 2 ab = = × + + − × = mJ 42 7 L 2 1 Wab= × ab× 2=