É !bܵ3
I. àƒbÜ
ƒb(function) àVH[ç/_‰b (value) 5MZ‰v, ª?ßÞú“/ᔥ@5Móú@5Zb, à f (x)g(x)¯U VH[ç‰b x 5ƒb Ê$l2àíƒbÜà-:
(1) f (x) = c, c ∈ R: ˚Ñb(constant) ƒb, w2 c ªJÑL<õb, ƒb f (x) .}Äщb x 5Z‰7‰
(2) f (x) = anxn+ an−1xn−1+ · · · + a1x+ a0, w2 ai∈ R, i = 1, 2, . . . , n,n ∈ N :f (x) ˚ÑÖá (polynomial)
Ñ|c5ƒb
(3) f (x) = eg(x): Nbƒb / e0= 1,e−∞= e1∞ = 0
(4) f (x) = logag(x): úbƒb (log function), ÑJ a Ñ5úbƒb, w2 a Ñøb (constant) |c5úbƒ bÑJAÍb e Ñ5ƒb, J f (x) = ln g(x) [ý I mn Ñs_b, úbƒbxJ-Ô4:
(i) logamn= logam+ logan (ii) logamn = logam− logan (iii) logamn= n logam (iv) loga1 = 0
(v) logaa= 1 (vi) x = eln x
II. }
}Ñ|à5bçj¶, Ê$l2:
} àk°ƒb5”M, Ê$l2àV°j©/Óœ‰b5VbêÞ5FÊ; £‚à|×–N¶
(maximum likelihood) V°j¡b|ª?êÞ5M
} àk°jƒbF¨Ö5Þ £ñ 5M, Ê$l2àV°j©/Óœ‰bÊ/¨–ÈêÞ5œ0(probability)
Ìb (mean) C‚M (expected value) £‰æb (variance) Ê$l2àí }tà-:
f(x) = c, c ∈ R f′(x) = 0 R
f(x)dx = cx + d
f(x) = cx, c ∈ R f′(x) = c R
f(x)dx = 12cx2+ d f(x) = cxn, c ∈ R, n ∈ N f′(x) = cnxn−1 R
f(x) = n+11 cxn+1+ d
f(x) = ex f′(x) = ex R
f(x)dx = ex+ d
f(x) = ecx f(x) = cecx R
f(x)dx = 1cecx+ d f(x) = ln x, x > 0, f′(x) = 1x
f(x) = 1x R
f(x)dx = ln |x| + d f(x) = ln g(x), g(x) > 0, f′(x) = g
′(x) g(x)
f(x) = cg(x) f′(x) = cg′(x) R
f(x)dx = cR g(x)dx f(x) = g(x) ± h(x) f′(x) = g′(x) ± h′(x) R
f(x)dx =R
g(x)dx ±R h(x)dx f(x) = g(x) · h(x) f′(x) = g′(x)h(x) + g(x)h′(x)
wFàí }t:
(1) ©ā¶† (chain rule): dydx = dydududx (2) ¶} }¶ (integration by parts): R
udv= uv −R vdu
Ex 1. I f (x) = b−a1 , w2 ab Ñs_b (constant), / b > a, ° (a) Rt
af(x)dx; (b) Rb
a xf(x) dx; (c) Rb
ax2f(x)dx (Sol.)
Note: Êœ02 f (x) = b−a1 Ñk a D b 5È5ÌG‰b (uniform random variable) 5œ0}ºƒb (probability distribution function),
• â (a) üæªø, J t ∈ [a, b], †Ú œ0ƒbÑP(X ≤ t) = t−ab−a
• â (b) üæªøRb
a xf(x)dx = E(X), FJÌG‰b5‚MÑ E(X) = a+b2
• â (c) üæªø, ÌGÓœ‰b5‰æb V (X) = E(X2) − [E(X)]2=13(b2+ ab + a2) − a+b2 2
=(a−b)12 2
Ex 2. I f (x) = λe−λxdx, w2 λ > 0 Ñøb, t° (a)Rt
0f(x)dx; (b)R∞
0 xf(x)dx; (c)R∞
0 x2f(x)dx (Sol.)
Note: Êœ02 f (x) = λe−λX,λ > 0 / x > 0, Ñ¡bÑ λ 5NbÓœ‰b (exponential random variable) 5œ0 }ºƒb (probability distribution function),
• â (a) üæªø, J t ∈ [a, b], †Ú œ0ƒbÑP(X ≤ t) = 1 − e−λt
• â (b) üæªøRb
a xf(x)dx = E(X), FJÌG‰b5‚MÑ E(X) = 1λ
• â (c) üæªø, ÌGÓœ‰b5‰æb V (X) = E(X2) − [E(X)]2=λ22 − λ12
=λ12
III. ,¸¯U
I a1, a2, . . . , an Ñøb, Êbç2‚à,¸¯U (P) VH[©/ n á5,¸, c5,¸tà-:
(1) I ai= c, w2 c Ñøb, † Pn i=1
ai= c + c + · · · + c
| {z }
n _ c ó‹
= n · c
(2) I ai= i, † Pn i=1
= 1 + 2 + · · · + n = n(n+1)2
(3) I ai= i2, † Pn i=1
= 12+ 22+ · · · + n2=n(n+1)(2n+1) 6
(4) I ai= a1ri−1, w2 a1∈ R, † a1, a2,· · · , an ÑøÌªb, †¤Ìªb5¸
Sn= Pn i=1
= a1+ a1r+ a1r2+ · · · + a1rn−1= a1(1 + r + · · · rn−1) = a1(1−r
n) 1−r
(5) I ai= a1ri−1, w2 a1∈ R / r < 1 † a1, a2, a3,· · · , ÑøÌ̪b, †¤Ì̪b5¸
S= P∞ i=1
= a1+ a1r+ a1r2+ · · · = a1(1 + r + r2+ · · · ) = 1−ra1
IV. lbj¶
Theorem ( ¶¶†)
JøK T.Û%âs_¥ VêA, ø_¥ ªâ m .°íj¶VêA, ù_¥ n .°íj¶VêA, †u ªJ m × n .°íj¶VêAv T
Theorem (‹¶¶†)
JøK TªJ‚às.°íj¶VêA, à‹ø_j¶ m j¶VêA, ù_j¶ n .°íj¶VêA, †u ªJ m + n .°íj¶VêA¤ T
Theorem
øÓñßå4í§¶˚ѧ (permutation)
(1) n _.°Óñ§íj¶ n! , w2 n! = n(n − 1)(n − 2) · · · 1
(2) * n _.°íÓñ2¦ r _ÓñV§, u Prn CnPr, w2 Prn =(n−r)!n! (3) * n _.°íÓñ2¦ r _ÓñV§, JcqªJ½º²¦, †u nr j¶
(4) n _Óñ2 k _Óñuó°í, †§j¶ n!k!
(5) n _Óñ, w2 k1_Óñuó°í,k2_Óñuó°í,. . ., ks_Óñuó°í, †ø n _ÓñV§uk n!
1!k2!···ks! Theorem
øÓñd³ßå4í§¶˚Ñ ¯ (combination)
(1) * n _.°íÓñ2¦ r _Óñ$Aø ¯íj¶ Crn CnCr , w2 Crn= r!(n−r)!n!
(2) * n _.°íÓñ2¦ n − r _Óñ$Aø ¯íj¶ Cn−rn C n−rCr, w2 Cn−rn = r!(n−r)!n! = Crn
Ex 3. ¬Ç, â A ƒ B •¡ (Ér →, ↑), t°
(1) â A ƒ B r¶í•¶?
(2) â A ƒ B .%¬ C í•¶?
(3) B* A •ƒ B, ~½B}%¬ C õíœ0Öý?
(Sol.)
Ex 4. An “all possible regressions” search of a data set containing 7 independent variables will produce . (93 «× F)
(A) 13 regressions (B) 48 regressions (C) 64 regressions (D) 127 regressions (E) none of the above
(Sol.)
Ex 5. øû.°ízJpú_.°íz*2, ©øz*.âz/*25z.ª¹¯, †uJ¶?
(Sol.)
Ex 6. t½å‚ PEPPER Öý.°í§?
(Sol.)
Ex 7. * 20 A2²¦ 3 A$Aøãº}, t½ A.°ãº}íj¶Öý?
(Sol.)
Ex 8. Of 10 people on a student newspaper staff, 6 are familiar with a particular word processing package. If three people are randomly selected as assigned to work as a team, how many ways could a team be selected in which one was familiar with the word processing package and the other two were not? (92 «× F)
(A) 24 (B) 120 (C) 20 (D) 36
(Sol.)
Theorem (Binomial Theorem)
(x + y)n= Xn i=1
Cinxiyn−i
(ax + by)n= Xn i=1
Cin(ax)i(by)n−i
Ex 9. ~½-Ç2,x3y4 í[bÑS?
(1) (x + y)7 (2) (3x + 4y)7
(Sol.)