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bçfÈ ùÿ»ú‚,…é"½ãlÞísd H«ìÜDìýìÜí„p ì ýìÜuH«ìÜÊéúi$,íR, …bÊ„pj¶,6æÊO.Íí:û "lÞàr
¼,„pH«ìÜíj¶„p7ìýìÜ, °6¿§óê; °vêÛ, Bb´ªJàwFj¶
V„p
1. =Ägj¶„pìýìÜ
=Äg 12 uv, Ê„ç¬ÞSí8”-, {!kúi$íóNÔ4, Ö Ë#|7 H«ìÜíø_„¶, ¥øj¶óçËÍ\¸À .¬, ¥øj¶1.u“h, ÄÑÊr¼ , Ÿ… 2˛%7¥„¶, ÉuÅHœõ
àÇ 1, Tòiúi$ ABC éi,íò CD, †4ABC, 4ACD, 4CBD ·u˛
¤óNí µó;WóNúi$2ú@iÅ5ªó (C6òQ‚ঠìÜ), AC2 = AD· AB, BC2 = BD · AB, só‹) AC2+ BC2 = (AD + BD) · AB = AB2
Ç 1 Ç 2
¥øj¶ªJRƒéúi$, BbJ@iúi$ÑW„pìýìÜ (iúi$ªJé NTÜ)
àÇ 2, Ê 4ABC 2, ¬ C õT(¨ CD, CE > AB k D, E, U∠ACD =∠B,
∠BCE = ∠A éÍ4ACD ∼ 4ABC ∼ 4CBE, ∴ AC2 = AD · AB, BC2 =
84
y}H«ìÜDìýìÜí„p 85
BE· AB, ACAB = C DBC 7∠CDE =∠CED =∠A+∠B, âìýì2ø,
cos(A + B) = cos∠CDE =
1 2DE
CD .
∴DE = 2CD · cos(A + B) = 2ACAB·BCcos(A + B)
∴ AC2+ BC2 = (AD + BE) · AB = (AB − DE) · AB = AB2 − DE · AB = AB2−2ACAB·BC cos(A+B)·AB = AB2−2AC ·BC cos(A+B) = AB2+2AC ·BC cos C
(¥êíi C N ∠ACB)
à¤Z„p7ìýìÜ ÊÇ 22, JD,E½¯, † ∠ACB Ñòi, ìýì܉ÑH«ì Ü
2. p,j¶„pìýìÜ
18764~, 1Å>>˚íu¸ö‡ºp,ê[7H«ìÜíø„¶ 1881F ç²1Å 20 L,$, ¥j¶6\˚Ñ,$j¶, AÑbçÍ,íø¨7u Fzs_r
íòiúi$:AàÇ 3 FýíÇ$, àsj¶lG$Þ , SG$ = 12(a + b)(a + b) = 2 ·12ab+ 12c2, “cÜ) a2+ b2 = c2
Ç3
‚à¥øj¶Bb.?òQ„pìýìÜ, OªJ„p sin(A + B), cos(A + B) t:
às_éiÅÌÑ 1 íòiúi$:AàÇ 4 FýíÇ$, àsj¶VlG$Þ , SG$ = 12(sin A+sin B)(cos A+cos B) = 12sin A cos A+12sin B cos B+12·1·1·sin(A+B),
“cÜ) sin(A + B) = sin A cos B + cos A sin B
86 bçfÈ 29 » 3 ‚ ¬ 94 9 ~
Ç 4 Ç 5
‚àH«ìܪø, vòiG$8ÅÑ q(cos A + cos B)2+ (sin A − sin B)2, ‚àú i$ìýìܪ)
cos(A + B) = − cos[π − (A + B)] = 12+ 12− [(cos A + cos B)2+ (sin A − sin B)2]
2 · 1 · 1 ,
“cÜ) cos(A + B) = cos A cos B − sin A sin B
p,j¶ÖÍ.?òQ„pìýìÜ, O§ sin(A + B), cos(A + B)t„p¬˙
íóê, Bbzs_éi}Ñ a,b íòiúi$àÇ5[0, ‚àH«ìÜ):
c2= (a cos A + b cos B)2 + (a sin A − b sin B)2
= a2cos2A+ 2ab cos A cos B + b2cos2B+ a2sin2A− 2ab sin A sin B + b2sin2B
= a2 + b2+ 2ab(cos A cos B − sin A sin B)
= a2 + b2+ 2ab cos(A + B) = a2+ b2− 2ab cos C.
.Øõ|, ¥wõu,H cos(A + B) t„píL¬˙ FJBbÛlàwFj¶ú
“cos A cos B − sin A sin B = cos(A + B)”tªW„p, yR|ìýìÜ, .Íÿ¸p7
=„
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