單元 24: 對數函數
( {… § 5.2)
q b > 0 / b 6= 1. Nbj˙
by = x, x > 0
íj y 4uU)b b í冪Ÿ (power) Ñ x ví冪 Ÿ, 1J
logb x [ý, ¹
y = logb x J/ñJ x = by, x > 0
/˚TJ b Ñí x íúb (logarithm of x to the base b). Wà, 根Wúbíì2,
(a) log10 100 = 2 (ÄÑ 100 = 102) (b) log5 125 = 3 (ÄÑ 125 = 53) (c) log3 271 = −3 (ÄÑ 1
27 = 3−3) (d) log20 20 = 1 (ÄÑ 20 = 201) (e) log1
2
16 = −4 (ÄÑ 16 = 1
2
−4)
(f ) log 1 10
0.01 = 2 (ÄÑ 0.01 = 1
10
2
)
註 .
ÄÑJ b ÑbíNbby = x > 0 恆Ñ£, ]c5?£bíúb
logb x, x > 0
W 1.
t°-®j˙íj.(a) log3 x = 4
(b) log16 4 = x
(c) logx8 = 3
(d) log1
2
4 = x
<j> (a) âúbíì2,
x = 34 = 81
(b) âì21“,
4 = 16x = (42)x = 42x ] x = 1
2.
(c) âì21“,
x3 = 8 = 23 ] x = 2.
(d) 根Wì21“,
1 2
x
= 4 = 22 =
1 2
−2
] x = −2.
ù_泛Uàíúb系$Ñ
1. J 10 Ñbíúb, ˚Tàúb (common logarithm) 1pA log, ¹
log x = log10 x, x > 0
2. JÌÜb e Ñbíúb, ˚TAÍúb (natural logarithm) 1pA ln, ¹
ln x = loge x, x > 0
Éúbíl, 藉Œk
úb律
(laws of logarithms). q m D n ѣb / b > 0, b 6= 1.1. logb mn = logb m + logb n
2. logb m
n = logb m − logb n 3. logb mn = n logb m
4. logb 1 = 0
5. logb b = 1
註 1.
úb律uÉ ¶, ζDŸj(¦úbí, .u‹¶, Á¶(¦úbí, øìbü-, 誤à, 6 ÿuz,logb(m + n) 6= logb m · logb n
C
logb(m − n) 6= logb m logb n
ÇÛ·<íu, úbí D}.k D}íú b, ¹
logb m · logb n 6= logb mn C
logb m
logb n 6= logb m n
註 2.
冪Ÿíúb律ªRBŠí冪Ÿ, ¹ logb m−n = logb 1mn = logb 1 − logb mn
= 0 − n logb m = −n logb m Ĥ, úL<õb r,
logb mr = r logb m
Wà,
(a) log(2 · 3) = log 2 + log 3
(b) ln 5
3 = ln 5 − ln 3 (c) log3 √
7 = 1
2 log3 7 (d) log5 1 = 0
(e) log45 45 = 1 (f ) log7 1
√5 = −1
2 log7 5
W 2.
#ìlog 2 ≈ 0.3010 D
log 3 ≈ 0.4771 J£
log 5 ≈ 0.6990 t°-®íM.
(a) log(15)
(b) log 7.5
(c) log 81
(d) log 50
(e) log 1 300
<j> (a) â 15 = 3 · 5 £úb律¶, ) log 15 = log 3 + log 5
≈ 0.4771 + 0.6990
= 1.1761 (b) ÄÑ
7.5 = 15
2 = 3 · 5 2 ]âúb律,
log 7.5 = log 3 + log 5 − log 2
≈ 0.4771 + 0.6990 − 0.3010
= 0.8751
(c) ÄÑ 81 = 34, ]âúb律, )
log 81 = 4 log 3 ≈ 4(0.4771) = 1.9084 (d) â 50 = 5 · 10 Dúb律, )
log 50 = log 5 + log 10
≈ 0.6990 + 1 = 1.6990 (e) â 300 = 3 · 102 Dúb律,
log 1
300 = − log 300 = −(log 3 + 2 log 10)
≈ −(0.4771 + 2) = −2.4771
W 3.
tÇ1“-®.(a) log3 x2y3
(b) log2 x2 + 1 2x
(c) ln x2
q
x2 − 1 ex
(d) ln x2
√x(1 + x)2
(e) ln xe−x2
<j> (a) âúb律, )
log3 x2y3 = log3 x2 + log3 y3
= 2 log3 x + 3 log3 y
(b) âúb律, ) log2 x2 + 1
2x = log2(x2 + 1) − log2 2x
= log2(x2 + 1) − x
(c) âúb律, ) ln x2
q
x2 − 1
ex = 2 ln x + 1
2 ln(x2 − 1) − x (d) 根Wúb律, )
ln x2
√x(1 + x)2 = 2 ln x − 1
2 ln x − 2 ln(1 + x)
(e) 根Wúb律,
ln xe−x2 = ln x + (−x2) ln e = ln x − x2 根Wúbíì2, )úbƒbí
ì2 .
q b > 0 / b 6= 1. ƒbf (x) def= logb x, x > 0
˚TJ b Ñbíúbƒb (logarithmic function with base b).
âúbíì2,
logb u = v J/ñJ bv = u, u > 0
¹, õ (u, v) Êúbƒb
y = logb x
íÇ$,J/ñJõ (v, u) ÊNbƒb y = bx
íÇ$,. ¢õ (u, v) Dõ (v, u) Jò( y = x Ñ 鏡射, 6ÿuz, úbƒb
y = logb x
íÇ$DNbƒb
y = bx íÇ$Jò( y = x Ñ鏡射.
Ĥ, Î7描õ¶Õ, ª根W鏡射¶, øNbƒbíÇ$ú ò( y = x 鏡射, )úbƒbíÇ$, àÇý.
根WÇý, )
úbƒbí4” .
úbƒby = logb x, (b > 0, b 6= 1), x > 0
à-í4”.
1. ì2域Ñ (0, ∞).
2. M域Ñ (−∞, ∞).
3. ¬õ (1, 0), ¹ logb 1 = 0.
4. Ê (0, ∞) ,©/, ¹恆©/.
5. Jb b > 1, Ê (0, ∞) ,遞Ó, ¹恆遞Ó; J
b 0 < b < 1, Ê (0, ∞) ,遞Á, ¹恆遞Á.
6. Jb b > 1, † lim
x→0+
logb x = −∞ / lim
x→∞ logb x = ∞ Jb 0 < b < 1, †
lim
x→0+
logb = ∞ / lim
x→∞ logb x = −∞
âúbíì2, )
Nú逆4 .
Nb«Dúb«Ñ逆«, ¹1. ø般b b > 0 / b 6= 1,
blogb x = x, x > 0 /
logb bx = x, −∞ < x < ∞
2. AÍNbƒbDAÍúbƒb,
eln x = x, x > 0
/
ln ex = x, −∞ < x < ∞
註 .
If (x) = bx, −∞ < x < ∞ /
g(x) = logb x, x > 0
†根W¯Aƒbí«d†DNú逆4,
(f ◦ g)(x) = f [g(x)] = f [logb x]
= blogb x = x, x > 0 /
(g ◦ f )(x) = g[f (x)] = g[bx]
= logb bx = x, −∞ < x < ∞
¹
f [g(x)] = x, x ∈ g íì2域 /
g[f (x)] = x, x ∈ f íì2域
1˚ f D g Ñ¥ƒb (inverse function), àÇý. 6ÿuz, NbƒbDúbƒbÑ¥ƒb, «u逆 í, ª彼¤J銷.
AÍNbDúbí逆4jZkjÖNbDúbíj˙, à
W 4.
tj-®j˙.(a) 2ex+2 − 7 = 5
(b) 5 ln x + 3 = 0
(c) 3 · 2−0.2t − 4 = 6
(d) 50
1 + 40e0.2t = 40
<j> (a) ácÜ, )
ex+2 = 7 + 5
2 = 6
s邊¦ ln 1根WNú逆4,
ln ex+2 = x + 2 = ln 6
¹
x = ln 6 − 2 ≈ −0.21
(b) ácÜ, )
ln x = −3 5 s邊¦ e 1根WNú逆4,
eln x = e−3/5
¹
x = e−3/5 ≈ 0.55
(c) ácÜ, )
2−0.2t = 10 3 s邊¦ ln 1“, )
−0.2t ln 2 = ln 10 3
]
t = −5 ln 103
ln 2 = −5(ln 10 − ln 3)
ln 2 ≈ −8.68 (d) ácÜ, )
1 + 40e0.2t = 5 4
¹
e0.2t = 1 40
5
4 − 1
= 1
160 s邊¦ ln 1“, )
0.2t = − ln 160 ]
t = −5 ln 160 ≈ −25.38
W 5.
qƒbf (x) = a + b ln x /˛ø
f (1) = 2 D f (2) = 4
t° f .
<j> H x = 1, )
a + b ln 1 = 2
¹
a + b(0) = 2 ] a = 2. yH x = 2 D a = 2, )
2 + b ln 2 = 4
¹
b = 4 − 2
ln 2 = 2 ln 2 Ĥ,
f (x) = 2 + 2 ln 2x